3x^2-150x-9000=0

Solution for 3x^2-150x-9000=0 equation:

3x^2-150x-9000=0

a = 3; b = -150; c = -9000;
Δ = b2-4ac
Δ = -1502-4·3·(-9000)
Δ = 130500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{130500}=\sqrt{900*145}=\sqrt{900}*\sqrt{145}=30\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-30\sqrt{145}}{2*3}=\frac{150-30\sqrt{145}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+30\sqrt{145}}{2*3}=\frac{150+30\sqrt{145}}{6}
$